 | William Chauvenet - 1852 - 268 pages
...120° 30' 30", c = 70° 20' 20", A = 50° 10' 10" ; find a. (Same as Ex. 1. p. 182). The formula is cos a = cos b cos c + sin b sin c cos A which will be thus computed : log cos b — 9.70557 log cos c + 9.52693 log q •— 9.23250 log sin... | |
 | Adrien Marie Legendre - Geometry - 1852 - 436 pages
...reducing to entire terms, we have, cos a — sin b sin c cos A = cos 6 cos c ; and by transposing, cos a — cos b cos c + sin b sin c cos A. A similar equation may be deduced for the cosine of either of the other sides : hence, cos a = cos... | |
 | Charles Davies - Geometry - 1854 - 436 pages
...this case must contain a, b, c, and A. The f1rst of equations (1) contains these four quantities : cos a = cos b cos c + sin b sin c cos A. If A = 90° cos A = 0 ; hence, cos a = cos b cos c • that is, radius, which is 1, into the sine of... | |
 | Paul Serret - 1855 - 168 pages
...ne doivent pas être retenues, et qu'il suffit d'apprendre à les lire rapidement sur la figure, i. cos a — cos b cos c + sin b sin c cos A. On a, dans le triangle rectiligno nbr, Remplaçant chaque ligne par sa valeur, réduisant au même... | |
 | Henry Barnard - Education - 1856 - 768 pages
...a sin. i — cot. A gin. C = cos. i cos. C, and by the consideration of the supplementary triangle cos. A = — cos. B cos. C + sin. B sin. C cos. a. Right-angled triangles. — Formulas cos. a — cos. Jcos. c; sin. i= sin. a sin. B; tang. e= tang,... | |
 | Adrien Marie Legendre, Charles Davies - Geometry - 1857 - 442 pages
...c' cos A1 : substituting for a', b', c' and A', their values from the polar triangle, we have, — cos A = cos B cos C — sin B sin C cos a ; and changing the signs of the terms, we obtain, cos A = sin B sin C cos a — cos B cos C. Similar... | |
 | John Hymers - Logarithms - 1858 - 292 pages
...two angles one of which is included by the sides; for instance between a, b, A, C. In the equation cos a = cos b cos c + sin b sin c cos A, substituting for cos c and sin c their values cos c -- cos a cos b + sin a sin b cos C, sin C sm c... | |
 | Chemistry - 1859 - 778 pages
...und x' gemessen hat. Bezeichnet man den Bogen M. N durch b und den Winkel WMN durch A, so hat man: cos a = cos b cos c + sin b sin c cos A cos a' — cos 6 cos c — sin & sin c cos A oder (3) . * . • , l a'+a a' — a COS 0 = COS - COS... | |
 | Isaac Todhunter - Spherical trigonometry - 1859 - 156 pages
...side; thus cos (TT — A) = cos (IT— -Z?)cos(ir — (7)+sin(7r— B) sin^-C") cos (TT—a), that is, cos A = - cos B cos C + sin B sin C cos a. Similarly cos B = - cos C cos A + sin C sin A cos b, and cos C = — cos A cos B + sin A sin B cos... | |
 | Chemistry - 1859 - 698 pages
...berechnen, wenn man nur für eine aufser z auch x und x' gemessen hat. Winkel WMN durch A, so hat man: cos a — cos b cos c + sin b sin c cos A cos a' — cos b cos c — sin b sin c cos A oder Bezeichnet man den Bogen MN durch b und den (3) ,... | |
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A cos 6 = cos a cos c + sin a sin c cos B cos c = cos a cos 6 + sin a sin 6 cos C Law of Cosines for Angles cos A = — cos B... 
